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Details for problem "Factorisation of terms"

Quickname: 8231

Suitable for grades: Grade 7, Grade 8, Grade 9

Summary

Factorise a term with variables

Example


Description

A term, which may contain up to three variables, has to be factorised. Common terms have to be factored out and put outside the brackets.

The shape of the factorised term, which is the answer to the problem, may be one of these:

a) 3*(x+6)
b) 3x*(y+6)
c) 3x*(x+7)
d) 3(2x+3y)
e) 3x(2x+3y)
f) 3(2x+3y+3z)

In the b,c,d and e variants, variables have to be factored out.
In the c and e variants, squares of variables may occur.

The term variants that may occur can be specified. The range for the numbers and products can be chosen. There is an option to choose whether negative numbers may be part of the term.

The number of problems is selectable. The first problem can be presented with the answer in the form of a sample problem. If required, some space will be left so that the answer may be written on the sheet.

Topics: Algebra

Tags: Multiplication, Rules, Terms

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Customization options for this problem

ParameterPossible values
Number of problems1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Number range20, 50, 99, 200, 499, 999, 1999, 4999
Negative numbers allowedYes, No
Sample problemYes, No
Space for answerYes, No
Problem type3(x+4), 3(x+4),3y(x+4), 3x(y+4),3x(x+4), 3(y+4),3(2x+3y), 3(2x+3y),3x(2x+3y), 3(2x+3y),3(2x+3y+4z), mixed, mixed no powers

Similar problems

RemarkDescriptionName and direct link
reverse operation: Expand productExpand product term with variables.Product term expansion



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