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Factorise a term with variables
A term, which may contain up to three variables, has to be factorised. Common terms have to be factored out and put outside the brackets.
The shape of the factorised term, which is the answer to the problem, may be one of these:
In the b,c,d and e variants, variables have to be factored out.
In the c and e variants, squares of variables may occur.
The term variants that may occur can be specified. The range for the numbers and products can be chosen. There is an option to choose whether negative numbers may be part of the term.
The number of problems is selectable. The first problem can be presented with the answer in the form of a sample problem. If required, some space will be left so that the answer may be written on the sheet.
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|Number of problems||1, 2, 3, 4, 5, 6, 7, 8, 9, 10|
|Number range||20, 50, 99, 200, 499, 999, 1999, 4999|
|Negative numbers allowed||Yes, No|
|Sample problem||Yes, No|
|Space for answer||Yes, No|
|Problem type||3(x+4), 3(x+4),3y(x+4), 3x(y+4),3x(x+4), 3(y+4),3(2x+3y), 3(2x+3y),3x(2x+3y), 3(2x+3y),3(2x+3y+4z), mixed, mixed no powers|
|Remark||Description||Name and direct link|
|identify expanded binomic formula in term and convert to original form by factoring it out or extracting summand||A binomic formula is hidden in a term. Factor out the binomic formular or extract the summand.||Extract binomic formula from term|
|reverse operation: Expand product||Expand product term with variables.||Product term expansion|