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Details for problem "Factorisation of terms"

Quickname: 8231

Suitable for K-12 grades: Grade 7 Grade 8 Grade 9

Junior High School, Middle School, High School.

Summary

Factorise a term with variables

Example

Factorise a term with variables (Beispiel für die Lösung)

Description

A term, which may contain up to three variables, has to be factorised. Common terms have to be factored out and put outside the brackets.

The shape of the factorised term, which is the answer to the problem, may be one of these:

a) 3*(x+6)
b) 3x*(y+6)
c) 3x*(x+7)
d) 3(2x+3y)
e) 3x(2x+3y)
f) 3(2x+3y+3z)

In the b,c,d and e variants, variables have to be factored out.
In the c and e variants, squares of variables may occur.

The term variants that may occur can be specified. The range for the numbers and products can be chosen. There is an option to choose whether negative numbers may be part of the term.

The number of problems is selectable. The first problem can be presented with the answer in the form of a sample problem. If required, some space will be left so that the answer may be written on the sheet.


Topics: Algebra

Tags: Multiplication Rules Terms

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Customization options for this problem

Parameter
Possible values
Number of problems
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Number range
20, 50, 99, 200, 499, 999, 1999, 4999
Negative numbers allowed
Yes, No
Sample problem
Yes, No
Space for answer
Yes, No
Problem type
3(x+4), 3(x+4),3y(x+4), 3x(y+4),3x(x+4), 3(y+4),3(2x+3y), 3(2x+3y),3x(2x+3y), 3(2x+3y),3(2x+3y+4z), mixed, mixed no powers

Similar problems

Remark
Description
Name and direct link
Identify expanded binomic formula in term and convert to original form by factoring it out or extracting summand
A binomic formula is hidden in a term. Factor out the binomic formular or extract the summand.
Reverse operation: Expand product
Expand product term with variables.


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